Divisibility by 5
 If the digit at the unit place is either 0 or 5 then the number is divisible by 5 else not.
Proof, How: Divisibility by Five
Let the number be abcd.
abcd can be written as
a×1000 + b×100 + c×10 + d
which can also be written as
a×5×200 + b×5×20 + c×5×2 + d
Every power of 10 i.e. 10 ^{x} is divisible by 5, where x is an integer.
So a×5×200 + b×5×20 + c×5×2 is divisible by 5 as it has 5 as factor or common factor.
The number is divisible by 5 if the last digit is 5 or zero.
Remainder on division by 5
 The remainder is the last digit (if last digit < 5) and (last digit  5) (if the last digit > 5).
Examples of division by 5
 Is 340 divisible by 5.
The last digit is 0 hence the number is divisible by 5.
 Is 3483 divisible by 5.
The remainder is the last digit (if last digit < 5) and (last digit  5) if the last digit > 5. As it is less than 5 therefore the remainder is the last digit i.e. 3.
 Is 377 divisible by 5.
The remainder is the last digit (if last digit < 5) and (last digit  5) if the last digit > 5.As it is greater than 5 therefore the remainder is the (last digit  5) i.e. (75) = 2.
